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"""Bisection algorithms."""
def insort_right(a, x, lo=0, hi=None): """Insert item x in list a, and keep it sorted assuming a is sorted.
If x is already in a, insert it to the right of the rightmost x.
Optional args lo (default 0) and hi (default len(a)) bound the slice of a to be searched. """
if hi is None: hi = len(a) while lo < hi: mid = (lo+hi)//2 if x < a[mid]: hi = mid else: lo = mid+1 a.insert(lo, x)
insort = insort_right # backward compatibility
def bisect_right(a, x, lo=0, hi=None): """Return the index where to insert item x in list a, assuming a is sorted.
The return value i is such that all e in a[:i] have e <= x, and all e in a[i:] have e > x. So if x already appears in the list, i points just beyond the rightmost x already there.
Optional args lo (default 0) and hi (default len(a)) bound the slice of a to be searched. """
if hi is None: hi = len(a) while lo < hi: mid = (lo+hi)//2 if x < a[mid]: hi = mid else: lo = mid+1 return lo
bisect = bisect_right # backward compatibility
def insort_left(a, x, lo=0, hi=None): """Insert item x in list a, and keep it sorted assuming a is sorted.
If x is already in a, insert it to the left of the leftmost x.
Optional args lo (default 0) and hi (default len(a)) bound the slice of a to be searched. """
if hi is None: hi = len(a) while lo < hi: mid = (lo+hi)//2 if a[mid] < x: lo = mid+1 else: hi = mid a.insert(lo, x)
def bisect_left(a, x, lo=0, hi=None): """Return the index where to insert item x in list a, assuming a is sorted.
The return value i is such that all e in a[:i] have e < x, and all e in a[i:] have e >= x. So if x already appears in the list, i points just before the leftmost x already there.
Optional args lo (default 0) and hi (default len(a)) bound the slice of a to be searched. """
if hi is None: hi = len(a) while lo < hi: mid = (lo+hi)//2 if a[mid] < x: lo = mid+1 else: hi = mid return lo
# Overwrite above definitions with a fast C implementation try: from _bisect import bisect_right, bisect_left, insort_left, insort_right, insort, bisect except ImportError: pass
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